- if x=y mod n then f(x) = f(y) mod n
Now let f be an arbitrary residue obeying function. Let's define sequence x(0) x(1) ... satisfy the following iterative equality:
- x(n+1) = f(x(n))
Then x(0) x(1)... is a prime residue obeying sequence, or pros for short, in the following sense:
- if x(i) = x(j) mod p then x(i+1) = x(j+1) mod m
Thus every pros mod p is eventually periodic:
indeed, let sequence x(0) x(1)... be a pros, and let p be a prime; then there are nonegative integers i < j ≤ p such that x(i) = x(j) mod p. Then starting with the index i, sequence x(n) is periodic mod p:
- x(n+d) = x(d) mod p
This means that if prime p didn't divide any of the terms x(0) ... x(j-1) then p does not divide any term of the infinite sequence x(0) x(1)....
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